30x^2+30x-19=0

Solution for 30x^2+30x-19=0 equation:

30x^2+30x-19=0

a = 30; b = 30; c = -19;
Δ = b2-4ac
Δ = 302-4·30·(-19)
Δ = 3180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3180}=\sqrt{4*795}=\sqrt{4}*\sqrt{795}=2\sqrt{795}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{795}}{2*30}=\frac{-30-2\sqrt{795}}{60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{795}}{2*30}=\frac{-30+2\sqrt{795}}{60}
$